Laws Of Motion Question 52

Question: A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is [IIT 1994]

Options:

A) 2.5 N

B)0.98 N

C) 4.9 N

D) 0.49 N

Show Answer

Answer:

Correct Answer: B

Solution:

Limiting friction $ F _{l}={{\mu } _{s}}R=0.5\times (5)=2.5\ N $

Since downward force is less than limiting friction therefore block is at rest so the static force of friction will work on it.

$ F _{s} $ = downward force = Weigh$ =0.1\times 9.8=0.98 $ N



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक