Laws Of Motion Question 45

Question: A body of mass M at rest explodes into three pieces, two of which of mass M/4 each are thrown off in perpendicular directions with velocities of 3 m/s and 4 m/s respectively. The third piece will be thrown off with a velocity of [CPMT 1990]

Options:

A) 1.5 m/s

B) 2.0 m/s

C) 2.5 m/s

D) 3.0 m/s

Show Answer

Answer:

Correct Answer: C

Solution:

Momentum of one piece =M4×3

Momentum of the other piece =M4×4

Resultant momentum =9M216+M2=5M4

The third piece should also have the same momentum.

Let its velocity be v, then 5M4=M2×v

or v=52=2.5m/sec



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक