SATHEE: Laws Of Motion Question 434

Laws Of Motion Question 434

Question: A rocket of initial mass 6000 kg ejects mass at a constant rate of 20 kg/s with constant relative speed of 10 km/s. What is the acceleration of the rocket after 50 second, (Neglect gravity)

Options:

A) $50 m / s^{2}$

B) $40 m / s^{2}$

C) $60 m / s^{2}$

D) 30 m/ $Ω$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Mass of the rocket after 50 seconds is: $m = m_{0} - μ t$

Here $μ = 20 k g / s$

$= (6000) - (20) (50) = 5000 k g$

Thrust force $F = V_{r e l μ}$

$∴$ $F = (10 \times 10^{3} m / s) (20 k g / s)$

$= 2.0 \times 10^{5} N$

$∴$ Acceleration $a = F / m = \frac{2 \times 10^{5}}{5000} = 40 m / s^{2}$

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Laws Of Motion Question 434

Question: A rocket of initial mass 6000 kg ejects mass at a constant rate of 20 kg/s with constant relative speed of 10 km/s. What is the acceleration of the rocket after 50 second, (Neglect gravity)

Options:

Answer:

Solution:

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