Laws Of Motion Question 432

Question: Two masses $ {m_1} $ and $ {m_2} $ are attached to the ends of a massless string which passes over a frictionless pulley attached to the top of an inclined plane. The angle of inclination of the plane is $ \theta $ . Take $ g=10m{{s}^{-2}} $ If$ m _{1}=10kg,m _{2}=5kg, $

$ \theta =30^{o}, $ what is the acceleration of mass $ m _{2} $ ?

Options:

A) zero

B) $ (2/3)m{{s}^{-2}} $

C) $ 5m{{s}^{-2}} $

D) $ 10/3m{{s}^{-2}} $

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ a=\frac{(m _{2}-m _{1}\sin \alpha )g}{(m _{1}+m _{2})}=\frac{(5-10\sin {{30}^{{}^\circ }})g}{(m _{1}+m _{2})}=0 $



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