SATHEE: Laws Of Motion Question 429

Laws Of Motion Question 429

Question: An explosion blows a rock into three parts. Two parts go off at right angles of each other. These two are 1 kg first part moving with a velocity of $12 m s^{- 1}$ and 2 kg second part moving with a velocity of $8 m s^{- 1}$ . If the third part files off with a velocity of $4 m s^{- 1},$ its mass would be :

Options:

A) 5 kg

B) 7 kg

C) 17 kg

D) 3 kg

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Apply law of conservation of linear momentum.

Momentum of first part $= 1 \times 12 = 12 k g m s^{- 1}$ . Momentum of the second part $= 2 \times 8 = 16 k g m s^{- 1}$ .

Resultant momentum $= \sqrt{{(12)}^{2} + {(16)}^{2}} = 20 k g m s^{- 1}$ .

The third part should also have the same momentum.

Let the mass of the third part be M, then $4 \times M = 20 \Rightarrow M = 5 k g$

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Laws Of Motion Question 429

Question: An explosion blows a rock into three parts. Two parts go off at right angles of each other. These two are 1 kg first part moving with a velocity of 12ms−1 and 2 kg second part moving with a velocity of8ms−1 . If the third part files off with a velocity of 4ms−1, its mass would be :

Options:

Answer:

Solution:

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