SATHEE: Laws Of Motion Question 427

Laws Of Motion Question 427

Question: Two particles A and B are connected by a rigid rod AB. The rod slides along perpendicular rails as shown here. The velocity of A to the left is 10 m/s. What is the speed of B when angle $θ = 45^{o} ?$

Options:

A) 5 m/s

B) (b) $5 \sqrt{2} m / s$

C) 10 m/s

D) 7.5 m/s

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $x^{2} + y^{2} = l^{2}$

$2 x \frac{d x}{d t} + 2 y \frac{d y}{d t} = 0$

$\Rightarrow$ $υ_{b} = \frac{x d x}{y d t} = 10 m / s$

$(x = y a t 45^{o})$

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Laws Of Motion Question 427

Question: Two particles A and B are connected by a rigid rod AB. The rod slides along perpendicular rails as shown here. The velocity of A to the left is 10 m/s. What is the speed of B when angle θ=45o?

Options:

Answer:

Solution:

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Question: Two particles A and B are connected by a rigid rod AB. The rod slides along perpendicular rails as shown here. The velocity of A to the left is 10 m/s. What is the speed of B when angle $θ = 45^{o} ?$