Laws Of Motion Question 427

Question: Two particles A and B are connected by a rigid rod AB. The rod slides along perpendicular rails as shown here. The velocity of A to the left is 10 m/s. What is the speed of B when angle $ \theta =45^{o}? $

Options:

A) 5 m/s

B) (b)$ 5\sqrt{2}m/s $

C) 10 m/s

D) 7.5 m/s

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $ x^{2}+y^{2}=l^{2} $

$ 2x\frac{dx}{dt}+2y\frac{dy}{dt}=0 $

$ \Rightarrow $ $ {{\upsilon } _{b}}=\frac{xdx}{ydt}=10m/s $

$ (x=yat45^{o}) $



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