Laws Of Motion Question 426

Question: The system is released from rest. The spring gets elongated

Options:

A) for M > m

B) for M > 2 m

C) for $ M>\frac{m}{2} $

D) for any value of M

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Net pulling force on the system is $ Mg+mgmg $ or Mg.

Total mass being pulled is$ M+2m. $ Hence, acceleration of the system is $ \sigma =\frac{Mg}{M+2m} $

Now since a < g. There should be an upwards force on m so that its acceleration becomes less than g.

Hence for any value of m spring will be elongated.



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