SATHEE: Laws Of Motion Question 337

Laws Of Motion Question 337

Question: A given object takes n times as much time to slide down a $45^{\circ}$ rough incline as it takes to slide down a perfectly smooth $45^{\circ}$ incline. The coefficient of friction between the object and the incline is

Options:

A) $(1 - 1 / n^{2})$

B) $1 / (1 - n^{2})$

C) $\sqrt{(1 - 1 / n^{2})}$

D) $1 / \sqrt{(1 - n^{2})}$

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Answer:

Correct Answer: A

Solution:

[a] $S m o o t h s u r f a c e,,, S = \frac{1}{2} g,, \sin,, θ,, {t_{1}}^{2} \dots . (i)$

$F o r rough s u r f a c e, a = g s i n, θ - μ,, \cos θ {t_{2}}^{2}$

$∴,, s = \frac{1}{2} g (s i n θ - μ c o s θ) {t_{2}}^{2}$ …(ii)

From (i) and (ii), $∴,, s = \frac{1}{2} g s i n θ {t_{1}}^{2} = \frac{1}{2} (s i n θ - μ c o s θ) {t_{2}}^{2}$ Given $θ = 45^{o} ∴ {t_{1}}^{2} = (1 - μ) {t_{2}}^{2}$

Also, given that. $t_{2} = n t_{1} ∴ {t_{1}}^{2} = (1 - μ) n^{2} {t_{1}}^{2}$

$\frac{1}{n^{2}} = 1 - μ ∴ μ = (1 - \frac{1}{n^{2}})$

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Laws Of Motion Question 337

Question: A given object takes n times as much time to slide down a $45^{\circ}$ rough incline as it takes to slide down a perfectly smooth $45^{\circ}$ incline. The coefficient of friction between the object and the incline is

Options:

Answer:

Solution:

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परीक्षा मंच

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सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Laws Of Motion Question 337

Question: A given object takes n times as much time to slide down a 45∘ rough incline as it takes to slide down a perfectly smooth45∘ incline. The coefficient of friction between the object and the incline is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: A given object takes n times as much time to slide down a $45^{\circ}$ rough incline as it takes to slide down a perfectly smooth $45^{\circ}$ incline. The coefficient of friction between the object and the incline is