Laws Of Motion Question 335

Question: A block A of mass 4 kg is placed on another block B of mass 5 kg, and the block B rests on a smooth horizontal table. If the minimum force that can be applied on A so that both the blocks move together is 12 N, the maximum force that can be applied to B for the blocks to move together will be:

Options:

A) 30 N

B) 25 N

C) 27 N

D) 48 N

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Minimum force on A =frictional force between the surfaces = 12 N

Therefore maximum acceleration $ {a _{\max }}=\frac{12N}{4kg}=3m/s^{2} $

Hence maximum force, $ {{F} _{max}}=totalmass\times a _{max}=9\times 3=27N $



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