Laws Of Motion Question 323

Question: Two blocks of mass $ M _{1}=20kg $ and $ M _{2}=12kg $ are connected by a metal rod of mass 8 kg. The system is pulled vertically up by applying a force of 480 N as shown. The tension at the mid-point of the rod is:

Options:

A) 144 N

B) 96 N

C) 240 N

D) 192 N

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Acceleration produced in upward direction

$ a=\frac{F}{M _{1}+M _{2}+\text{Mass of metal rod}} $

=$ \frac{480}{20+12+8}=12\text{ m}{{s}^{-2}} $

Tensions at the mid-point $ T=( M _{2}+\frac{\text{Mass of rod}}{2} )a $

$ =( 12+4 )\times 12=192N $



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