SATHEE: Laws Of Motion Question 323

Laws Of Motion Question 323

Question: Two blocks of mass $M_{1} = 20 k g$ and $M_{2} = 12 k g$ are connected by a metal rod of mass 8 kg. The system is pulled vertically up by applying a force of 480 N as shown. The tension at the mid-point of the rod is:

Options:

A) 144 N

B) 96 N

C) 240 N

D) 192 N

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Acceleration produced in upward direction

$a = \frac{F}{M_{1} + M_{2} + Mass of metal rod}$

= $\frac{480}{20 + 12 + 8} = 12 m s^{- 2}$

Tensions at the mid-point $T = (M_{2} + \frac{Mass of rod}{2}) a$

$= (12 + 4) \times 12 = 192 N$

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Laws Of Motion Question 323

Question: Two blocks of mass M1=20kg and M2=12kg are connected by a metal rod of mass 8 kg. The system is pulled vertically up by applying a force of 480 N as shown. The tension at the mid-point of the rod is:

Options:

Answer:

Solution:

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Question: Two blocks of mass $M_{1} = 20 k g$ and $M_{2} = 12 k g$ are connected by a metal rod of mass 8 kg. The system is pulled vertically up by applying a force of 480 N as shown. The tension at the mid-point of the rod is: