Laws Of Motion Question 278

Question: A particle of mass 0.3 kg subject to a force $ F=-kx $ with$ k=15N/m $ . What will be its initial acceleration if it is released from a point 20 cm away from the origin?

Options:

A) $ 15m/s^{2} $

B) $ 3m/s^{2} $

C) $ 10m/s^{2} $

D) $ 5m/s^{2} $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $ Mass( m )=0.3kg\Rightarrow F=m.a=-15x $

$ a=-\frac{15}{0.3}x=\frac{-150}{3}x=-50x $

$ a=-50\times 0.2=10\text{ m/}{{m}^{2}} $



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