SATHEE: Laws Of Motion Question 268

Laws Of Motion Question 268

Question: A gardner waters the plants by a pipe of diameter 1mm. The water comes out at the rate or 10 cm3/sec. The reactionary force exerted on the hand of the gardner is [KCET 2000]

Options:

A) Zero

B) $1.27 \times 10^{- 2} N$

C) $1.27 \times 10^{- 4} N$

D) $0.127 N$

Show Answer

Answer:

Correct Answer: D

Solution:

Rate of flow of water $\frac{V}{t} = \frac{10 c m^{3}}{\sec} = 10 \times 10^{- 6} \frac{m^{3}}{\sec}$

Density of water $ρ = \frac{10^{3} k g}{m^{3}}$

Cross-sectional area of pipe $A = π {(0.5 \times 10^{- 3})}^{2}$

Forcse $= m \frac{d v}{d t} = \frac{m v}{t} = \frac{V ρ v}{t} = \frac{ρ V}{t} \times \frac{V}{A t} = {(\frac{V}{t})}^{2} \frac{ρ}{A}$

$(∵ v = \frac{V}{A t})$ By substituting the value in the above formula we get $F = 0.127 N$

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Laws Of Motion Question 268

Question: A gardner waters the plants by a pipe of diameter 1mm. The water comes out at the rate or 10 cm3/sec. The reactionary force exerted on the hand of the gardner is [KCET 2000]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Laws Of Motion Question 268

Question: A gardner waters the plants by a pipe of diameter 1mm. The water comes out at the rate or 10 cm3/sec. The reactionary force exerted on the hand of the gardner is [KCET 2000]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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