Laws Of Motion Question 264

Question: n small balls each of mass m impinge elastically each second on a surface with velocity u. The force experienced by the surface will be [MP PMT/PET 1998; RPET 2001; BHU 2001; MP PMT 2003]

Options:

A) mnu

B) 2 mnu

C) 4 mnu

D) $ \frac{1}{2}mnu $

Show Answer

Answer:

Correct Answer: B

Solution:

$ \vec{F}=\frac{d\vec{p}}{dt}= $

Rate of change of momentum As balls collide elastically hence, rate of change of momentum of ball = $ n[mu-(mu)] $ = $ 2mnu $ i.e. $ F=2mnu $



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