SATHEE: Laws Of Motion Question 246

Laws Of Motion Question 246

Question: An automobile travelling with a speed of $60 k m / h,$ can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]

Options:

A) 20 m

B) 40 m

C) 60 m

D) 80 m

Show Answer

Answer:

Correct Answer: D

Solution:

The stopping distance, $S \propto u^{2}$

$(∵ v^{2} = u^{2} - 2 a s)$

therefore $\frac{S_{2}}{S_{1}} = {(\frac{u_{2}}{u_{1}})}^{2} = {(\frac{120}{60})}^{2} = 4$

therefore $S_{2} = 4 \times S_{1} = 4 \times 20 = 80 m$

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Laws Of Motion Question 246

Question: An automobile travelling with a speed of $60 k m / h,$ can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

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अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Laws Of Motion Question 246

Question: An automobile travelling with a speed of 60km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: An automobile travelling with a speed of $60 k m / h,$ can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]