Laws Of Motion Question 245

Question: A machine gun fires a bullet of mass 40 g with a velocity 1200ms1. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most[AIEEE 2004]

Options:

A) One

B) Four

C) Two

D) Three

Show Answer

Answer:

Correct Answer: D

Solution:

u = velocity of bullet dmdt=

Mass fired per second by the gun dmdt = Mass of bullet (mB) × Bullets fired per sec (N)

Maximum force that man can exert F=u (dmdt)

F=u×mB×N

therefore N=FmB×u=14440×103×1200=3



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