Laws Of Motion Question 238
Question: A monkey of mass 20kg is holding a vertical rope. The rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope $ (g=10m/s^{2}) $ [CBSE PMT 2003]
Options:
A) $ 10m/s^{2} $
B) $ 25m/s^{2} $
C) $ 2.5m/s^{2} $
D) $ 5m/s^{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
Tension the string $ =m(g+a)= $ Breaking force therefore $ 20(g+a)=25\times g $
therefore $ a=g/4=2.5\ m/s^{2} $
