Laws Of Motion Question 233
Question: A block of mass $ 5kg $ is moving horizontally at a speed of 1.5 m/s. A perpendicular force of 5N acts on it for 4 sec. What will be the distance of the block from the point where the force started acting [Pb. PMT 2002]
Options:
A) 10 m
B) 8 m
C) 6 m
D) 2 m
Show Answer
Answer:
Correct Answer: A
Solution:
$ {S _{Horizontal}}=ut=1.5\times 4=6m $
$ {S _{Vertical}}=\frac{1}{2}at^{2}=\frac{1}{2}\frac{F}{m}t^{2}=\frac{1}{2}\times 1\times 16=8m $
$ {S _{Net}}=\sqrt{6^{2}+8^{2}}=10m $
