Laws Of Motion Question 233

Question: A block of mass 5kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force of 5N acts on it for 4 sec. What will be the distance of the block from the point where the force started acting [Pb. PMT 2002]

Options:

A) 10 m

B) 8 m

C) 6 m

D) 2 m

Show Answer

Answer:

Correct Answer: A

Solution:

SHorizontal=ut=1.5×4=6m

SVertical=12at2=12Fmt2=12×1×16=8m

SNet=62+82=10m



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