Laws Of Motion Question 233

Question: A block of mass $ 5kg $ is moving horizontally at a speed of 1.5 m/s. A perpendicular force of 5N acts on it for 4 sec. What will be the distance of the block from the point where the force started acting [Pb. PMT 2002]

Options:

A) 10 m

B) 8 m

C) 6 m

D) 2 m

Show Answer

Answer:

Correct Answer: A

Solution:

$ {S _{Horizontal}}=ut=1.5\times 4=6m $

$ {S _{Vertical}}=\frac{1}{2}at^{2}=\frac{1}{2}\frac{F}{m}t^{2}=\frac{1}{2}\times 1\times 16=8m $

$ {S _{Net}}=\sqrt{6^{2}+8^{2}}=10m $



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