Laws Of Motion Question 226

Question: A 30 gm bullet initially travelling at 120 m/s penetrates 12 cm into a wooden block. The average resistance exerted by the wooden block is [AFMC 1999; CPMT 2001]

Options:

A) 2850N

B) 2200 N

C) 2000N

D) 1800 N

Show Answer

Answer:

Correct Answer: D

Solution:

$ F=\frac{m(u^{2}-v^{2})}{2S}=\frac{30\times {{10}^{-3}}\times {{(120)}^{2}}}{2\times 12\times {{10}^{-2}}}=1800N $



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