Laws Of Motion Question 222
Question: An army vehicle of mass 1000 kg is moving with a velocity of 10 m/s and is acted upon by a forward force of 1000N due to the engine and a retarding force of 500 N due to friction. What will be its velocity after 10 s[Pb. PMT 2000]
Options:
A) 5 m/s
B) 10 m/s
C) 15 m/s
D) 20 m/s
Show Answer
Answer:
Correct Answer: C
Solution:
$ v=u+\frac{F}{m}t=10+( \frac{1000-500}{1000} )\times 10=15m/s $
