Laws Of Motion Question 222

Question: An army vehicle of mass 1000 kg is moving with a velocity of 10 m/s and is acted upon by a forward force of 1000N due to the engine and a retarding force of 500 N due to friction. What will be its velocity after 10 s[Pb. PMT 2000]

Options:

A) 5 m/s

B) 10 m/s

C) 15 m/s

D) 20 m/s

Show Answer

Answer:

Correct Answer: C

Solution:

v=u+Fmt=10+(10005001000)×10=15m/s



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