Laws Of Motion Question 212
Question: A mass of 10 gm is suspended by a string and the entire system is falling with a uniform acceleration of $ 400cm/{{\sec }^{2}}. $ The tension in the string will be $ (g=980cm/{{\sec }^{2}}) $ [SCRA 1994]
Options:
A)5,800 dyne
B) 9,800 dyne
C) 11,800 dyne
D) 13,800 dyne
Show Answer
Answer:
Correct Answer: A
Solution:
$ T=m(g-a) $ = 10(980 ? 400) = 5800 dyne
