Laws Of Motion Question 212

Question: A mass of 10 gm is suspended by a string and the entire system is falling with a uniform acceleration of $ 400cm/{{\sec }^{2}}. $ The tension in the string will be $ (g=980cm/{{\sec }^{2}}) $ [SCRA 1994]

Options:

A)5,800 dyne

B) 9,800 dyne

C) 11,800 dyne

D) 13,800 dyne

Show Answer

Answer:

Correct Answer: A

Solution:

$ T=m(g-a) $ = 10(980 ? 400) = 5800 dyne



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