Laws Of Motion Question 207

Question: The time period of a simple pendulum measured inside a stationary lift is found to be T. If the lift starts accelerating upwards with an acceleration g/3, the time period is [EAMCET 1994; CMEET Bihar 1995; RPMT 2000]

Options:

A) T3

B) T3/2

C) T/3

D) T/3

Show Answer

Answer:

Correct Answer: B

Solution:

T=2πlg and T=2πl4g/3

[As g=g+a=g+g3=4g3 ] T=

32T



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