Laws Of Motion Question 198
Question: A vehicle of 100 kg is moving with a velocity of 5 m/sec. To stop it in $ \frac{1}{10}\sec $ , the required force in opposite direction is [MP PET 1995]
Options:
A)5000 N
B) 500 N
C) 50 N
D) 1000 N
Show Answer
Answer:
Correct Answer: A
Solution:
$ F=m\ ( \frac{dv}{dt} )=\frac{100\times 5}{0.1}=5000\ N $
