Laws Of Motion Question 198

Question: A vehicle of 100 kg is moving with a velocity of 5 m/sec. To stop it in $ \frac{1}{10}\sec $ , the required force in opposite direction is [MP PET 1995]

Options:

A)5000 N

B) 500 N

C) 50 N

D) 1000 N

Show Answer

Answer:

Correct Answer: A

Solution:

$ F=m\ ( \frac{dv}{dt} )=\frac{100\times 5}{0.1}=5000\ N $



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