Laws Of Motion Question 195

Question: A body of mass 4 kg weighs 4.8 kg when suspended in a moving lift. The acceleration of the lift is [Manipal MEE 1995]

Options:

A) $ 9.80m{{s}^{-2}} $ downwards

B) 9.80$ m{{s}^{-2}} $ upwards

C) 1.96$ m{{s}^{-2}} $ downwards

D) 1.96$ m{{s}^{-2}} $ upwards

Show Answer

Answer:

Correct Answer: D

Solution:

As the apparent weight increase therefore we can say that acceleration of the lift is in upward direction. $ R=m(g+a) $ therefore$ 4.8\ g=4(g+a) $ therefore$ a=0.2g=1.96\ m/s^{2} $



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