Laws Of Motion Question 171

Question: A diwali rocket is ejecting 0.05 kg of gases per second at a velocity of 400 m/sec. The accelerating force on the rocket is [NCERT 1979; DPMT 2001; MP PMT 2004]

Options:

A)20 dynes

B) 20 N

C) 22 dynes

D) 1000 N

Show Answer

Answer:

Correct Answer: B

Solution:

$ F=u( \frac{dm}{dt} )=400\times 0.05=20\ N $



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