SATHEE: Laws Of Motion Question 141

Laws Of Motion Question 141

Question: A house is built on the top of a hill with $45^{\circ}$ slope. Due to the sliding of material and sand from top to the bottom of hill, the slope angle has been reduced. If the coefficient of static friction Between sand particles is 0.75, what is the final angle attained by hill? $(t a n^{- 1} 0.75 ≃ 37^{0})$

Options:

A) $8^{\circ}$

B) $45^{\circ}$

C) $37^{\circ}$

D) $30^{\circ}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] As sand particles are sliding down, the slope of the hill gets reduced.

The sand particle stops coming down when component of gravity force along the hill is balanced by limiting friction force.

$m g \sin θ = μ_{s} m g \cos θ$

$\Rightarrow θ = \tan^{- 1} (μ_{s}) ≃ 37^{\circ}$ Where $θ$ is the new slope angle of hill.

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Laws Of Motion Question 141

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu