SATHEE: Laws Of Motion Question 140

Laws Of Motion Question 140

Question: The upper half of an inclined plane with inclination $ϕ$ is perfectly smooth while the lower half is rough. A body starting from rest at the top will again come to rest at the bottom if the coefficient of friction for the lower half is given by

Options:

A) $2 \tan ϕ$

B) $\tan ϕ$

C) $2 s i n ϕ$

D) $2 \cos ϕ$

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Answer:

Correct Answer: A

Solution:

[a] For first half acceleration $= g s i n ϕ$

Therefore, velocity after travelling half distance $v^{2} = 2 (g s i n ϕ) l$ (i)

For second half, acceleration $= g (s i n ϕ - μ_{k} c o s ϕ)$

So $0^{2} = v^{2} + 2 g (s i n ϕ - μ_{k} c o s ϕ) l$ (ii) Solving (i) and (ii), we get $μ_{k} = 2 \tan ϕ$

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Laws Of Motion Question 140

Question: The upper half of an inclined plane with inclination $ϕ$ is perfectly smooth while the lower half is rough. A body starting from rest at the top will again come to rest at the bottom if the coefficient of friction for the lower half is given by

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Laws Of Motion Question 140

Question: The upper half of an inclined plane with inclination ϕ is perfectly smooth while the lower half is rough. A body starting from rest at the top will again come to rest at the bottom if the coefficient of friction for the lower half is given by

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: The upper half of an inclined plane with inclination $ϕ$ is perfectly smooth while the lower half is rough. A body starting from rest at the top will again come to rest at the bottom if the coefficient of friction for the lower half is given by