SATHEE: Laws Of Motion Question 139

Laws Of Motion Question 139

Question: A tube of length $L$ is filled completely with an incompressible liquid of mass $M$ and closed at both the ends. The tube is then rotated in horizontal plane about one of its ends with a uniform angular velocity $ω$ . The force exerted by the liquid at the other end is

Options:

A) $\frac{M L ω^{2}}{2}$

B) $M L ω^{2}$

C) $\frac{M L ω^{2}}{4}$

D) $\frac{M L^{2} ω^{2}}{2}$

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Answer:

Correct Answer: A

Solution:

[a] $d M = (\frac{M}{L}) d x$

Force on dM mass is $d F = (d M) ω^{2} x$

By integration, we can get the force exerted by whole liquid

$\Rightarrow F = \int_{0}^{L} \frac{M}{L} ω^{2} x d x = \frac{1}{2} M ω^{2} L$

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Laws Of Motion Question 139

Question: A tube of length $L$ is filled completely with an incompressible liquid of mass $M$ and closed at both the ends. The tube is then rotated in horizontal plane about one of its ends with a uniform angular velocity $ω$ . The force exerted by the liquid at the other end is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Laws Of Motion Question 139

Question: A tube of length L is filled completely with an incompressible liquid of mass M and closed at both the ends. The tube is then rotated in horizontal plane about one of its ends with a uniform angular velocity ω . The force exerted by the liquid at the other end is

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: A tube of length $L$ is filled completely with an incompressible liquid of mass $M$ and closed at both the ends. The tube is then rotated in horizontal plane about one of its ends with a uniform angular velocity $ω$ . The force exerted by the liquid at the other end is