Laws Of Motion Question 136

Question: The system starts from rest and A attains a velocity of 5 m/s after it has moved 5 m towards right. Assuming the arrangement to be frictionless everywhere and pulley and strings to be light, the value of the constant force F applied on A is

Options:

A) 50 N

B) 75 N

C) 100 N

D) 96 N

Show Answer

Answer:

Correct Answer: B

Solution:

[b] a=v22s=2510=2.5m/s2

For6kg:F2T=6a(i)

For2kg:T2g=2(2a)(ii) From (i) and (ii), F=75N



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