Laws Of Motion Question 123

Question: A fireman of mass 60 kg slides down a pole.He is pressing the pole with a force of 600 N.The coefficient of friction between the hands and the pole is 0.5, with what acceleration will the fireman slide down (g = 10 m/s2)[Pb. PMT 2002]

Options:

A) 1 m/s2

B) 2.5 m/s2

C) 10 m/s2

D) 5 m/s2

Show Answer

Answer:

Correct Answer: D

Solution:

Net downward acceleration =Weight-Friction forcem

=(mgμ R)m

=60×100.5×60060

=30060=5 m/s2



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