Laws Of Motion Question 121

Question: A body of mass 5kg rests on a rough horizontal surface of coefficient of friction 0.2.The body is pulled through a distance of 10m by a horizontal force of 25 N.The kinetic energy acquired by it is (g = 10 ms2) [EAMCET (Med.) 2000]

Options:

A) 330 J

B) 150 J

C) 100 J

D) 50 J

Show Answer

Answer:

Correct Answer: B

Solution:

Kinetic energy acquired by body = (Total work done on the body) ? (work against friction)$ =F\times S-\mu mgS=25\times 10-0.2\times 5\times 10\times 10 $

$ =250-100=150\ Joule $



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