Laws Of Motion Question 117

Question: A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction m = 0.5.If a horizontal force of 100 N is acting on it, then acceleration of the block will be [AIIMS 2002]

Options:

A) $ 0.5m/s^{2} $

B) $ 5m/s^{2} $

C) $ 10m/s^{2} $

D) $ 15m/s^{2} $

Show Answer

Answer:

Correct Answer: B

Solution:

$ a=\frac{\text{Applied force –Kinetic friction}}{m} $

$ =\frac{100-0.5\times 10\times 10}{10}=5m/s^{2} $



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