Laws Of Motion Question 116

Question: A body of weight 64 N is pushed with just enough force to start it moving across a horizontal floor and the same force continues to act afterwards.If the coefficients of static and dynamic friction are 0.6 and 0.4 respectively, the acceleration of the body will be (Acceleration due to gravity = g) [EAMCET 2001]

Options:

A) $ \frac{g}{6.4} $

B) 0.64 g

C) $ \frac{g}{32} $

D) 0.2 g

Show Answer

Answer:

Correct Answer: D

Solution:

Weight of the body = 64N so mass of the body

$ m=6.4\ kg $ ,$ {{\mu } _{s}}=0.6 $ ,

$ {{\mu } _{k}}=0.4 $ Net acceleration $ =\frac{\text{Applied force -Kinetic friction}}{\text{Mass of the body}} $

$ =\frac{{{\mu } _{s}}mg-{{\mu } _{k}}mg}{m}=({{\mu } _{s}}-{{\mu } _{k}})g=(0.6-0.4)g=0.2g $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक