Laws Of Motion Question 115
Question: A vehicle of mass m is moving on a rough horizontal road with momentum P. If the coefficient of friction between the tyres and the road be m, then the stopping distance is [CBSE PMT 2001]
Options:
A) $ \frac{P}{2\mu mg} $
B) $ \frac{P^{2}}{2\mu mg} $
C) $ \frac{P}{2\mu m{{}^{2}}g} $
D) $ \frac{P^{2}}{2\mu m{{}^{2}}g} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ S=\frac{u^{2}}{2\mu g}=\frac{m^{2}u^{2}}{2\mu gm^{2}}=\frac{P^{2}}{2\mu m^{2}g} $
