Laws Of Motion Question 110
Question: Consider a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of kinetic friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is $ [g=10m{{s}^{-2}}] $ [CBSEPMT 1992]
Options:
A) 30 m
B) 40 m
C) 72 m
D) 20 m
Show Answer
Answer:
Correct Answer: B
Solution:
$ s=\frac{u^{2}}{2\mu \ g}=\frac{{{(20)}^{2}}}{2\times 0.5\times 10}=40\ m $
