Laws Of Motion Question 108

Question: A body of 10 kg is acted by a force of 129.4 N if g=9.8m/sec2 . The acceleration of the block is10m/s2 . What is the coefficient of kinetic friction[EAMCET 1994]

Options:

A) 0.03

B) 0.01

C) 0.30

D) 0.25

Show Answer

Answer:

Correct Answer: C

Solution:

Net force on the body = Applied force ? Friction ma=Fμkmg thereforeμk=Fmamg=129.410×1010×9.8=0.3



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