Kinematics Question 788

Question: A person with his hands in his pockets it’s skating on ice at the velocity of 10 m/s and describes a circle of radius 50 m. What is his inclination with vertical [Pb. PET 2000]

Options:

A) $ \frac{\sqrt{3}}{2}. $

B)$ {{\tan }^{-1}}( \frac{3}{5} ) $

C) $ {{\tan }^{-1}}(1) $

D) $ {{\tan }^{-1}}( \frac{1}{5} ) $

Show Answer

Answer:

Correct Answer: D

Solution:

The inclination of person from vertical it’s given by, $ \tan \theta =\frac{v^{2}}{rg}=\frac{{{(10)}^{2}}}{50\times 10}=\frac{1}{5} $ $ \theta ={{\tan }^{-1}}(1/5) $



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