Kinematics Question 773
Question: If a cyclist moving with a speed of 4.9 m/s on a level road can take a sharp circular turn of radius 4 m, then coefficient of friction between the cycle tyres and road is [AIIMS 1999; AFMC 2001]
Options:
A) 0.41
B) 0.51
C) 0.61
D) 0.71
Show Answer
Answer:
Correct Answer: C
Solution:
$ \mu =\frac{v^{2}}{rg}=\frac{{{(4.9)}^{2}}}{4\times 9.8}=0.61 $