Kinematics Question 758

Question: If a particle covers half the circle of radius R with constant speed then[RPMT 2000]

Options:

A) Momentum change it’s mvr

B) Change in K.E. it’s 1/2 mv2

C) Change in K.E. it’s mv2

D) Change in K.E. is zero

Show Answer

Answer:

Correct Answer: D

Solution:

As momentuM is vector quantity \ change in momentum $ \Delta P $ = $ 2mv\sin (\theta /2) $ =$ 2mv\sin (90)=2mv $ But kinetic energy remains always constant so change in kinetic energy is zero.



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