SATHEE: Kinematics Question 726

Kinematics Question 726

Question: The length of second’s hand in a watch is 1 cm. The change in velocity of it’s tip in 15 seconds is[MP PMT 1987, 2003]

Options:

A) Zero

B) $\frac{π}{30 \sqrt{2}} c m / \sec$

C) $\frac{π}{30} c m / \sec$

D) $\frac{π \sqrt{2}}{30} c m / \sec$

Show Answer

Answer:

Correct Answer: D

Solution:

In 15 second’s hand rotate through $90^{\circ}$ .

Change in velocity $| \vec{Δ v} | = 2 v \sin (θ / 2)$

$= 2 (r ω) \sin (90^{\circ} / 2)$

$= 2 \times 1 \times \frac{2 π}{T} \times \frac{1}{\sqrt{2}}$

$= \frac{4 π}{60 \sqrt{2}} = \frac{π \sqrt{2}}{30} \frac{c m}{\sec}$ [As T = 60 sec]

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Kinematics Question 726

Question: The length of second’s hand in a watch is 1 cm. The change in velocity of it’s tip in 15 seconds is[MP PMT 1987, 2003]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu