Kinematics Question 719

Question: A motor cyclist moving with a velocity of 72 km/hour on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 meters. The acceleration due to gravity it’s 10 m/sec2. In order to avoid skidding, he must not bend with respect to the vertical plane by an angle greater than[CPMT 1986]

Options:

A) $ \theta ={{\tan }^{-1}}6 $

B)$ \theta ={{\tan }^{-1}}2 $

C) $ \theta ={{\tan }^{-1}}25.92 $

D)$ \theta ={{\tan }^{-1}}4 $

Show Answer

Answer:

Correct Answer: B

Solution:

$ v=72km/hour=20m/\sec $

$ \theta ={{\tan }^{-1}}( \frac{v^{2}}{rg} )={{\tan }^{-1}}( \frac{20\times 20}{20\times 10} )={{\tan }^{-1}}(2) $



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