Kinematics Question 695

Question: The greatest height to which a man can throw a stone is $ \sqrt{\frac{F}{mr}} $ . The greatest distance to which he can throw it, will be

Options:

A) $ 2\pi r^{2}/T $

B) $ \upsilon ,\upsilon \text{ and }\upsilon $

C) $ 2h $

D) $ 3h $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] For greatest height $ \theta =90{}^\circ $

$ {H _{\max }}=\frac{u^{2}{{\sin }^{2}}(90{}^\circ )}{2g}=\frac{u^{2}}{2g}=h $

(given)$ {R _{\max }}=\frac{u^{2}{{\sin }^{2}}2(45{}^\circ )}{g}=\frac{u^{2}}{g}=2h $



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