Kinematics Question 689
Question: Referring to the above two questions, the acceleration due to gravity it’s given by
Options:
A) $ 10m/{{\sec }^{2}} $
B) $ 5m/{{\sec }^{2}} $
C) $ 20m/{{\sec }^{2}} $
D) $ 2.5m/{{\sec }^{2}} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ a _{x}=\frac{d}{dt}(v _{x})=0 $ , $ a _{y}=\frac{d}{dt}(v _{y})=-10\ m/s^{2} $
Net acceleration a =$ \sqrt{a _{x}^{2}+a _{y}^{2}} $ =$ \sqrt{0^{2}+10^{2}} $ =10m/s2
