Kinematics Question 671
Question: A ball is rolled off the edge of a horizontal table at a speed of 4 m/second.It his the ground after 0.4 second.Which statement given below it’s true
Options:
A) It his the ground at a horizontal distance 1.6 m from the edge of the table
B) The speed with which it his the ground it’s 4.0 m/second
C) Height of the table it’s 0.8 m
D) It his the ground at an angle of $ 60^{o} $ to the horizontal
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Answer:
Correct Answer: A , C
Solution:
(a,c) Vertical component of velocity of ball at point P
$ v _{V}=0+gt=10\times 0.4=4m/s $
Horizontal component of velocity = initial velocity
$ \Rightarrow v _{H}=4m/s $
So the speed with which it his the ground
$ v=\sqrt{v _{H}^{2}+v _{V}^{2}}=4\sqrt{2}m/s $
and $ \tan \theta =\frac{v _{V}}{v _{H}}=\frac{4}{4}=1 $
therefore $ \theta =45{}^\circ $
It means the ball his the ground at an angle of $ 45{}^\circ $ to the horizontal. Height of the table
$ h=\frac{1}{2}gt^{2}=\frac{1}{2}\times 10\times {{(0.4)}^{2}}=0.8m $
Horizontal distance travelled by the ball from the edge of table
$ h=ut=4\times 0.4=1.6m $
Same us above
