Kinematics Question 645

Question: It was calculated that a shell when fired from a gun with a certain velocity and at an angle of elevation $ 5\pi /36 $ rad should strike a given target. In actual practice, it was found that a hill just prevented the trajectory. At what angle (rad) of elevation should the gun be fired to hit the target

Options:

A) $ \frac{5\pi }{36} $

B)$ \frac{11\pi }{36} $

C) $ \frac{7\pi }{36} $

D)$ \frac{13\pi }{36} $

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Answer:

Correct Answer: D

Solution:

[d] Ranges for complementary angles are same $ \therefore $ Required angle $ \text{=}\frac{\pi }{2}-\frac{5\pi }{36}=\frac{13\pi }{36} $



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