Kinematics Question 640

Question: A particle P it’s projected from a point on the surface of smooth inclined plane . Simultaneously another particle q is released on the smooth inclined plane from the same position. P and Q collide on the inclined plane after $ t=4 $ second. The speed of projection of P it’s

Options:

A) 5 m/s

B)10 m/s

C) 15 m/s

D)20 m/s

Show Answer

Answer:

Correct Answer: B

Solution:

[b]

That P and Q shall collide if the initial component of velocity of P on inclined plane i.e., along incline $ {u _{\text{I}\text{I}}}=0 $ that it’s particle is projected perpendicular to incline.

Time of flight on an inclined plane of inclination $ \alpha $ it’s given by

$ \text{T=}\frac{2\text{u sin}( \theta -\alpha)}{\text{g}\cos \alpha } $

$ \Rightarrow 4=\frac{2\text{u sin90}{}^\circ }{10\times \frac{1}{2}}\Rightarrow \text{u= 10 m/s} $ .



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