SATHEE: Kinematics Question 635

Kinematics Question 635

Question: A jet plane flying at a constant velocity v at a height $h = 8 k m$ , it’s being tracked by a radar R located at O directly below the line of flight. If the angle $θ$ it’s decreasing at the rate of $0.025 r a d / s$ , the velocity of the plane when $θ = 60^{\circ}$ it’s:

Options:

A) 1440 km/h

B)960 km/h

C) 1920 km/h

D)480 km/h

Show Answer

Answer:

Correct Answer: B

Solution:

[b]

$x = h \cot θ$

$∴ \frac{d x}{d t} = h \frac{d (\cot θ)}{d t}$

$= h (- cose c^{2} θ) \frac{d θ}{d t}$

$or v = h cose c^{2} θ (- \frac{d θ}{d t})$

$= (8 \times 10^{3}) cose c^{2} 60^{\circ} \times 0.025 = 2666.67 m/s$

$= 960 km/h$

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Kinematics Question 635

Question: A jet plane flying at a constant velocity v at a height h=8km , it’s being tracked by a radar R located at O directly below the line of flight. If the angle θ it’s decreasing at the rate of 0.025rad/s , the velocity of the plane when θ=60∘ it’s:

Options:

Answer:

Solution:

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Question: A jet plane flying at a constant velocity v at a height $h = 8 k m$ , it’s being tracked by a radar R located at O directly below the line of flight. If the angle $θ$ it’s decreasing at the rate of $0.025 r a d / s$ , the velocity of the plane when $θ = 60^{\circ}$ it’s: