Kinematics Question 6

Question: An object of m kg with speed of v m/s strikes a wall at an angle q and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will be

Options:

A) 2mvcosθ

B) 2mvsinθ

C) 0

D) 2mv

Show Answer

Answer:

Correct Answer: A

Solution:

P1=mvsinθi^mvcosθj^

and P2=mvsinθi^+mvcosθj^

So change in momentum ΔP=P2P1=2mvcosθj^,

|ΔP|=2mvcosθ



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