SATHEE: Kinematics Question 592

Kinematics Question 592

Question: The position of particle is given by $\vec{r} = 2 t^{2} \hat{i} + 3 t \hat{j} + 4 \hat{k},$ where $t$ it’s in second and the coefficients have proper unit for $\vec{r}$ to be in meter. The $\vec{a} (t)$ of the particle at $t = 1 s$ it’s

Options:

A) $4 m s^{- 2}$ along y-direction

B) $3 m s^{- 2}$ along x-direction

C) $4 m s^{- 2}$ along x-direction

D) $2 m s^{- 2}$ along z-direction

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Answer:

Correct Answer: C

Solution:

[c] $\vec{r} = 2 t^{2} \hat{i} + 3 t \hat{j} + 4 \hat{k}$

$∴ \vec{v} = \frac{d \vec{r}}{d t} = \frac{d}{d t} = (2 t^{2} \hat{i} + 3 t \hat{j} + 4 \hat{k}) = 4 t \hat{i} + 3 \hat{j}$

$\vec{a} = \frac{d \vec{v}}{d t} = \frac{d}{d t} (4 t \hat{i} + 3 \hat{j}) = 4 \hat{i}$

$∴ \vec{a} = 4 m s^{- 2} along x-direction$

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Kinematics Question 592

Question: The position of particle is given by $\vec{r} = 2 t^{2} \hat{i} + 3 t \hat{j} + 4 \hat{k},$ where $t$ it’s in second and the coefficients have proper unit for $\vec{r}$ to be in meter. The $\vec{a} (t)$ of the particle at $t = 1 s$ it’s

Options:

Answer:

Solution:

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Kinematics Question 592

Question: The position of particle is given by r→=2t2i^+3tj^+4k^, where t it’s in second and the coefficients have proper unit for r→ to be in meter. The a→(t) of the particle at t=1s it’s

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: The position of particle is given by $\vec{r} = 2 t^{2} \hat{i} + 3 t \hat{j} + 4 \hat{k},$ where $t$ it’s in second and the coefficients have proper unit for $\vec{r}$ to be in meter. The $\vec{a} (t)$ of the particle at $t = 1 s$ it’s