Kinematics Question 576
Question: Two balls are projected at an angle $ \theta $ and $ (90{}^\circ -\theta ) $ to the horizontal with the same speed. The ratio of their maximum vertical heights it’s B Tricky
Options:
A) 1:1
B)$ \text{tan}\theta :1 $
C) $ 1:\text{tan}\theta $
D)$ \text{ta}{{n^{2}}\theta :1 $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ \frac{{{\text{H}} _{\text{1}}}}{{{\text{H}} _{\text{2}}}}\text{=}\frac{{u^{2}}{{\sin }^{2}}\theta /\text{2g}}{{u^{2}}{{\sin }^{2}}( 90{}^\circ -\theta)/2\text{g}}={{\tan }^{2}}\theta $
