SATHEE: Kinematics Question 543

Kinematics Question 543

Question: A weightless thread can support tension upto 30 N. A stone of mass 0.5 kg it’s tied to it and it’s revolved in a circular path of radius 2 m in a vertical plane. If $g = 10 m / s^{2}$ , then the maximum angular velocity of the stone will be[MP PMT 1994]

Options:

A) $5 r a d / s$

B) $\sqrt{30} r a d / s$

C) $\sqrt{60} r a d / s$

D) $10 r a d / s$

Show Answer

Answer:

Correct Answer: A

Solution:

$T_{max} = m ω_{^{max}}^{2} r + m g$

therefore $\frac{T_{max}}{m} = ω^{2} r + g$

therefore $\frac{30}{0.5} - 10 = {ω^{2}}_{max} r$

therefore $ω_{max} = \sqrt{\frac{50}{r}} = \sqrt{\frac{50}{2}} = 5 r a d / s$

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Kinematics Question 543

Question: A weightless thread can support tension upto 30 N. A stone of mass 0.5 kg it’s tied to it and it’s revolved in a circular path of radius 2 m in a vertical plane. If g=10m/s2 , then the maximum angular velocity of the stone will be[MP PMT 1994]

Options:

Answer:

Solution:

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Question: A weightless thread can support tension upto 30 N. A stone of mass 0.5 kg it’s tied to it and it’s revolved in a circular path of radius 2 m in a vertical plane. If $g = 10 m / s^{2}$ , then the maximum angular velocity of the stone will be[MP PMT 1994]